1) Santhosh packed 240 oranges and 288 apples in boxes. He packed oranges and apples in separate boxes. He put equal number of fruits in each box. What is the maximum number of fruits that can be put in each box?​

Answer:

a

Step-by-step explanation:

g(1)=5

f(g(1))=f(5)

f(5)=2

Step-by-step explanation:

- 6x - 6 - 2x = 40. collect the like terms

- 6x - 2x - 6 = 40

- 8x - 6 = 40 take 6 to the right

- 8x = 40 + 6

- 8x/ -8 = 46/ - 8

x = - 5.75

I hope this answers your question

Answer:

[tex]thank \: you[/tex]

Answer:

Option A, 4

Step-by-step explanation:

f(-2) = -(-2)³-3×(-2)²+8

= 8-12+8

= 16-12

= 4

Answer:

Step-by-step explanation:

Answer:

[tex]f(x) = 6 \\ f( - 6) = 6 \\ because \: here \: function \: is \: \\ independent \: of \: x \\ thank \: you[/tex]

Answer:

Because, function f(x) is independent of x

So, the value of f(x) is +6 everywhere

Therefore, f(-6) = +6

Answer:

n is 13

Step-by-step explanation:

[tex] {n}^{2} = {12}^{2} + {6}^{2} - (2 \times 12 \times 6) \cos(90 \degree) \\ {n}^{2} = 180 \\ n = 13.4[/tex]

Answer:

n is 13

Step-by-step explanation:

Answer:

Line of symmetry of f is x=2 and the line of symmetry for function g is x=1 as the graph starts repeating itself after x=1. Y intercept is the point at which x is 0, for f it is - 5 and for g it is - 6. Rate of change in interval [2,4] is given by (f(4)-f(2))/2=2 for f and for g it is, (g(4)-g(2))/2=-4

The true statements are:

This is the point where the function is divided into equal halves.

From the figure, the table and graph are divided at points x = 2, and x = 1.

So, the line of symmetry for function f is x = 2 and the line of symmetry for function g is x = 1

This is the point where the function has an x value of 0

From the figure, the y values when x = 0 are -5 and -6

So, the y-intercept of function f is -5 and the y-intercept of function g is -6

This is calculated as:

[tex]m = \frac{y_2 - y_1}{x_2 -x_1}[/tex]

For function f, we have:

[tex]m = \frac{-5 + 9}{4-2}[/tex]

[tex]m = \frac{4}{2}[/tex]

[tex]m = 2[/tex]

For function g, we have:

[tex]m = \frac{2+ 6}{4-2}[/tex]

[tex]m = \frac{8}{2}[/tex]

[tex]m = 4[/tex]

By comparison,

[tex]m_f = 0.5 \times m_g[/tex]

Hence, over the interval [2, 4], the average rate of change of function f is half the average rate of change of function g.

Read more about functions and graphs at:

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Answer:

32х+14

Step-by-step explanation:

[tex]2(9x + 5 + 7x + 2) \\ 18x + 10 + 14x + 4 \\ 32x + 14[/tex]

Answer:

32x + 14

Step-by-step explanation:

The opposite sides of a rectangle are equal, so

perimeter = 2(9x + 5) + 2(7x + 2) ← distribute parenthesis

                 = 18x + 10 + 14x + 4 ← collect like terms

                 = 32x + 14

Answer:

Radius is 39.89422804 units

Step-by-step explanation:

Area of circle can be calculated with the formula: [tex]\pi r^{2}[/tex]

The area of the circle is 5000.

[tex]\pi r^{2}[/tex]= 5000

If you're looking for the radius, solve for r.

[tex]r^{2}[/tex]= [tex]\frac{5000}{\pi }[/tex]

r= [tex]\sqrt{\frac{5000}{\pi} }[/tex]

r= 39.89422804 units

Answer:

Step-by-step explanation:

It is convenient to let a graphing calculator show the answers to these questions.

The exponential equation modelling the growth will be of the form ...

  f(x) = (initial value) × (1 +growth rate)^x

Richland's GDP/person can be modeled by r(x) = 10·1.01^x

Poorland's GCP/person can be modeled by p(x) = 5·1.03^x

The attached graph shows values for x=5, 10 and r(x)=p(x).

It will take about 35.3 years for Poorland to catch up.

Answer:

5

Step-by-step explanation:

Mode is which number occurs most, and in this set of data, 5 occurs two times.

Answer:

The volume can be found by multiplying these two numbers, which is

65/4 x 1/2

65/8 units^3

Let me know if this helps!

Answer:

8 1/8 units ^3

Step-by-step explanation:

The volume is given by

V = Bh where B is the area of the base and h is the height

V = 16 1/4 * 1/2

Changing to an improper fraction

V = ( 4*14+1)/4 * 1/2

  = (65/4) * 1/2

  = 65/8

Changing back to a mixed number

  = 8 1/8

Answer:

(x - 8)^2 + (y + 1)^2 = 68

Step-by-step explanation:

The standard form of the equation of the circle with center (8,−1) is :

(x - 8)^2 + (y + 1)^2 = R^2

If the circle passes through the point (6,7) that means that the point (6,7) is a solution of the equation and we can replace (x,y) with (6,7) to find R.

The distance between Balloon B and Balloon A is 999 feet (correct to the nearest whole number); that is, Balloon B is 999 feet from balloon A

The diagram for the question is shown as described in the question in the attachment below.

From the diagram,

Let the height from balloon A to the ground be /AG/ and the height from balloon B to the ground be /BD/ and the point where Charlie is be C

/AG/ = 1200 feet

/AG/ = /BD/ = 1200 feet ( as shown in the diagram)

The distance between the two balloons is equal to /GD/

Also, from the diagram, /GD/ = /GC/ + /CD/

To find /GC/,

Consider ΔAGC

/AG/ = 1200 feet

/GC/ = ?

From the question, "Balloon A has risen at a 56° angle"

∴ x° = 56°

Using the formula

[tex]tan(x^{o} ) = \frac{/AG/}{/GC/}[/tex]

[tex]tan(56^{o}) = \frac{1200}{/GC/}[/tex]

[tex]/GC/ = \frac{1200}{tan(56^{o}) }[/tex]

/GC/ = 809.41 feet

To find /CD/

Consider ΔBCD

/BD/ = 1200 feet

/CD/ = ?

From the question, "Balloon B has risen at a 81° angle"

∴ y° = 81°

Using the formula

[tex]tan(y^{o} ) = \frac{/BD/}{/CD/}[/tex]

[tex]tan(81^{o}) = \frac{1200}{/CD/}[/tex]

[tex]/CD/ = \frac{1200}{tan(81^{o}) }[/tex]

/CD/ = 190.06 feet

Now, recall that /GD/ = /GC/ + /CD/

∴ /GD/ = 809.41 feet + 190.06 feet

/GD/  = 999.47 feet

/GD/ ≅ 999 feet (to  the nearest whole number)

Hence, the distance between the two balloons is 999 feet

Balloon B is 999 feet from balloon A.

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Answer:

999 Units

Step-by-step explanation:

what

Step-by-step explanation:

pretty sure its 25 percent

Answer:

25%

Step-by-step explanation:

if you take half of 50 it is 25 so all of it is used or 25%

Hope this helps <3 Comment if you want more thanks and be sure to give brainliest (4 left) <3

Answer:

2x^31

Step-by-step explanation:

~Simplify the expression

2x^29/x^-2

~Apply quotient rule [ a^b/a^c = a^b-c ]

2x^31

Best of Luck~

Answer:

Step-by-step explanation:

Used identities:

Jane is given a $100 gift to start and saves $35 a month from her allowance.

   After 1 month, Jane has saved

   After 2 months, Jane has saved

   After three months, Jane has saved

   and so on

In general, after x months Jane has saved

This means that it makes sense to represent the relationship between the amount saved and the number of months with one constant rate (in this case the constant rate is 35). It makes sense because the amount of money increases by $35 each month. Since the amount of increase is constant, we get constant rate. Also the initial amount is known ($100), so there is a possibility to write the equation of linear function representing this situation.

Step-by-step explanation:

9514 1404 393

Answer:

  2.5%

Step-by-step explanation:

Simple interest is computed using the formula ...

  I = Prt . . . . for principal P invested at rate r for t years

Using the given values, we can solve for r ...

  67.50 = 900r·3

  r = 67.50/2700 = 0.025 = 2.5%

Megan's account earned 2.5% interest.

Answer:

lol

Step-by-step explanation:

Now don't get us wrong – not all of these answers raise this excellent question

The value of [tex]\mu[/tex] = 29.6, M = 31.9, [tex]\sigma[/tex] = 16 , s = 22.4, [tex]\sigma_m[/tex] = 3.121, and [tex]\rm S_m[/tex] = 2.473.

It is given that the mean break time per day from the most recent census is 29.6 minutes with a standard deviation of 16 minutes.

It is required to organize the information in a table if the sample size is 82.

It is defined as an error that gives an idea about the percentage of errors that exist in the real statistical data.

The formula for finding the MOE:

[tex]\rm MOE = Z_{score}\frac{s}{\sqrt[]{n} }[/tex]

Where    is the z score at the confidence interval

            s is the standard deviation

            n is the number of samples.

We know:

[tex]\rm \sigma_m= \frac{\sigma^2}{n}[/tex]

We have,

[tex]\rm \sigma = 16 \ and \ n = 82[/tex]

[tex]\rm \sigma_m= \frac{16^2}{82}[/tex]

[tex]\rm \sigma_m= 3.121[/tex]

For [tex]\rm S_m[/tex]

[tex]\rm S_m = \frac{s}{\sqrt{n} }[/tex]

We have,

s = 22.4 and n = 82

[tex]\rm S_m = \frac{22.4}{\sqrt{82} }[/tex]

[tex]\rm S_m = 2.473[/tex]

Thus, the value of [tex]\mu[/tex] = 29.6, M = 31.9, [tex]\sigma[/tex] = 16 , s = 22.4, [tex]\sigma_m[/tex] = 3.121, and [tex]\rm S_m[/tex] = 2.473.

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Answer:

Step-by-step explanation:

Distance between (2,1) and (3,3) = √5

parametric equations for circle of radius √5, centered at (2,1):

x = √5cosθ+2

y = √5sinθ+1

At (3,3), θ = arccos(1/√5) ≅ 63.4°

After 45° transformation:

θ' = 63.4° + 45° = 108.4°

x' = √5cos(108.4°)+2 = 1.29

y' = √sin(108.4°)+1 = 3.12

(3,3) transformed to (1.29,3.12)

Notice that

6 + 7 = 13

13 + 7 = 20

so if the pattern continues, the underlying sequence in this series is arithmetic with first term a = 6 and difference d = 7. This means the k-th term in the sequence is

a + (k - 1) d = 6 + 7 (k - 1) = 7k - 1

The last term in the series is 111, which means the series consists of 16 terms, since

7k - 1 = 111   ==>   7k = 112   ==>   k = 16

Then in summation notation, we have

[tex]\displaystyle 6+13+20+\cdots+111 = \boxed{\sum_{k=1}^{16}(7k-1)}[/tex]

Answer:

1/8 is less than

Step-by-step explanation:

i dont see any fractions below gona have to edit your answer

Answer:

[tex]{ \bf{ \frac{dy}{dx} = \frac{3 - 4x}{4y + 2} }}[/tex]

Step-by-step explanation:

[tex]{ \sf{ \frac{dy}{dx} (2 {x}^{2} + 2 {y}^{2} - 3x + 2y = 1) }} \\ \\ { \sf{4x + 4y \frac{dy}{dx} - 3 + 2 \frac{dy}{dx} = 0 }} \\ \\ { \sf{ 4y\frac{dy}{dx} + 2 \frac{dy}{dx} = 3 - 4x }} \\ \\ { \sf{ \frac{dy}{dx}(4y + 2) = 3 - 4x }} \\ \\ { \sf{ \frac{dy}{dx} = \frac{3 - 4x}{4y + 2} }}[/tex]

[tex]{ \underline{ \tt{ \blue{christ \:† \: alone }}}}[/tex]

The cost of the cereal if the grocery store buys 250 boxes is $475

We know that:

The cost function is:

c(n) = 2*n              if n < 100

c(n) = 1.9*n            if  100 ≤ n ≤ 500

c(n) = 1.8*n            if   n > 500.

(we can assume that the cost function is in dollars)

This is a piecewise function, this means that we need to see in which interval we have the number n, and then select the correct function to use.

Now, we want to find the cost of the cereal if the store buys 250 boxes.

Then we have n = 250.

We can see that n = 250 is in the second interval,  100 ≤ n ≤ 500, then we will use the second function to find the cost.

We will get:

c(250) = 1.9*(250) = $475

We can conclude that the cost if the store buys 250 boxes is 475

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Answer:

Step-by-step explanation:

334.488 miles

Answer:

Step-by-step explanation:

770 = 2*5*7*11

So they are:

2*385

10*77

5*154

7*110

14*55

11*70

22*35

By Green's theorem, the line integral

[tex]\displaystyle \int_C f(x,y)\,\mathrm dx + g(x,y)\,\mathrm dy[/tex]

is equivalent to the double integral

[tex]\displaystyle \iint_D \frac{\partial g}{\partial x} - \frac{\partial f}{\partial y} \,\mathrm dx\,\mathrm dy[/tex]

where D is the region bounded by the curve C, provided that this integrand has no singularities anywhere within D or on its boundary.

It's a bit difficult to make out what your integral should say, but I'd hazard a guess of

[tex]\displaystyle \int_C \left(3y+5e^{-x}\right)\,\mathrm dx + \left(10x+3\cos\left(y^2\right)\right)\,\mathrm dy[/tex]

Then the region D is

D = {(x, y) : 0 ≤ x ≤ 1 and x ² ≤ y ≤ √x}

so the line integral is equal to

[tex]\displaystyle \int_0^1\int_{x^2}^{\sqrt x} \frac{\partial\left(10x+3\cos\left(y^2\right)\right)}{\partial x} - \frac{\partial\left(3y+5e^{-x}\right)}{\partial y}\,\mathrm dy\,\mathrm dx \\\\ = \int_0^1 \int_{x^2}^{\sqrt x} (10-3)\,\mathrm dy\,\mathrm dx \\\\ = 7\int_0^1 \int_{x^2}^{\sqrt x} \mathrm dy\,\mathrm dx[/tex]

which in this case is 7 times the area of D.

The remaining integral is trivial:

[tex]\displaystyle 7\int_0^1\int_{x^2}^{\sqrt x}\mathrm dy\,\mathrm dx = 7\int_0^1y\bigg|_{y=x^2}^{y=\sqrt x}\,\mathrm dx \\\\ = 7 \int_0^1\left(\sqrt x-x^2\right)\,\mathrm dx \\\\ = 7 \left(\frac23x^{3/2}-\frac13x^3\right)\bigg|_{x=0}^{x=1} = 7\left(\frac23-\frac13\right) = \boxed{\frac73}[/tex]