1. A curious physics student drops a book from a high building.
A. What is the VELOCITY of the brick after 3.0s?
B. How FAR(Distance) does the book fall during this time?

2. Suppose a free-fall ride at an amusement park starts at a rest and then drops.
A. What is the VELOCITY of the ride after 2.5s?
B. How FAR do people on the ride fall during the 2.5s time period?

3. You throw a ball downward from a window at a speed of 3.0 m/s.
A. How FAST will it be moving when it hits the sidewalk 2.0m below?

4. If I drop a photo copier off of a 45m tall building and splats on the ground below:
A. Calculate the TIME to hit the ground:
B. Calculate the VELOCITY just before:

Answers

Answer 1

Answer:

1.

A. Vf = 29.4 m/s

B. h = 44.1 m

2.

A. Vf = 24.5 m/s

B. h = 30.625 m

3.

A. Vf = 5.5 m/s

4.

A. t = 3.03 s

B. Vf = 29.7 m/s  

Explanation:

1.

A.

using 1st equation of motion:

Vf = Vi + gt

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 0 m/s (since, book starts from rest)

g = 9.8 m/s²

t = time = 3 s

Therefore,

Vf = 0 m/s + (9.8 m/s²)(3 s)

Vf = 29.4 m/s

B.

using 2nd equation of motion:

h = Vi t + (1/2)gt²

h = (0 m/s)(3 s) + (1/2)(9.8 m/s²)(3 s)²

h = 44.1 m

2.

A.

using 1st equation of motion:

Vf = Vi + gt

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 0 m/s (since, book starts from rest)

g = 9.8 m/s²

t = time = 2.5 s

Therefore,

Vf = 0 m/s + (9.8 m/s²)(2.5 s)

Vf = 24.5 m/s

B.

using 2nd equation of motion:

h = Vi t + (1/2)gt²

h = (0 m/s)(2.5 s) + (1/2)(9.8 m/s²)(2.5 s)²

h = 30.625 m

3.

A.

using 3rd equation of motion:

2gh = Vf² - Vi²

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 3 m/s

g = 9.8 m/s²

h = height = 2 m

Therefore,

2(9.8 m/s²)(2 m) = Vf² - (3 ms)²

Vf² = 39.2 m²/s² - 9 m²/s²

Vf = √30.2 m²/s²

Vf = 5.5 m/s

4.

A.

using 2nd equation of motion:

h = Vi t + (1/2)gt²

where,

h = height = 45 m

Vi = Initial Velocity = 0 m/s (since, photo copier was initially at rest)

t = time = ?

g = 9.8 m/s²

45 m = (0 m/s)(t) + (1/2)(9.8 m/s²)(t)²

t² = 2(45 m)/(9.8 m/s²)

t = √9.18 s²

t = 3.03 s

B.

using 1st equation of motion:

Vf = Vi + gt

Vf = 0 m/s + (9.8 m/s²)(3.03 s)

Vf = 29.7 m/s


Related Questions

A nail driven into a board increases in temperature.
If 59.0 % of the kinetic energy delivered by a 1.60 kg hammer with a speed of 7.70 m/s is transformed into heat that flows into the nail and does not flow out, what is the increase in temperature of an 7.60 g aluminum nail after it is struck 10 times?

Answers

Answer:

ΔT = 40.91 °C

Explanation:

First we find the kinetic energy of one hit to the nail:

K.E = (1/2)mv²

where,

K.E = Kinetic energy = ?

m = mass of hammer = 1.6 kg

v = speed of hammer = 7.7 m/s

Therefore,

K.E = (1/2)(1.6 kg)(7.7 m/s)²

K.E = 47.432 J

Now, for 10 hits:

K.E = (10)(47.432 J)

K.E = 474.32 J

Now, we calculate the heat energy transferred (Q) to the nail. As, it is the 59% of K.E. Therefore,

Q = (0.59)K.E

Q = (0.59)(474.32 J)

Q = 279.84 J

The change in energy of nail is given as:

Q = mCΔT

where,

m = mass of nail = 7.6 g = 0.0076 kg

C = specific heat capacity of aluminum = 900 J/kg.°C

ΔT = Increase in temperature = ?

Therefore,

279.84 J = (0.0076 kg)(900 J/kg.°C)ΔT

ΔT = (279.84 J)/(6.84 J/°C)

ΔT = 40.91 °C

Check how you understand the principles of working of lenses. In some optical setup consisting of a single lens and an object magnification factor is measured as m-+4. We can conclude that:__________ a. Lens is converging, image is at the opposite side of lens from the object b. Lens is converging, image is the same side of lens as object c. Lens is diverging, image is at the opposite side of lens from the object d. Lens is diverging, image is the same side of lens as object

Answers

Answer:

b. Lens is converging, image is the same side of lens as object

Explanation:

A single converging lens is often used as a magnifying glass. The reason, behind its use as a magnifying glass is the configuration of the converging lens, when an object is placed inside its focal length. It forms the image of that object as magnified and at the same side as the object. So, the image is both magnified and erect. In this way, the converging lens serves as a magnifying glass with certain magnification factor, single handedly. The ray diagram of a magnifying glass is attached for reference. So, the correct option is:

b. Lens is converging, image is the same side of lens as object

30.6*X+-2.56
Pls help

Answers

Answer:  10.16

Explanation:

an object with a mass of 7.5 kg accelerates 8.3 m/s2 when an unknown force is applied to it. what is the amount of the force?

Answers

Answer:

I believe the answer is 62.25 N

Explanation:

You just multiply 7.5 and 8.3 and you get 62.25

Answer:

62.25N or 62.25 newtons

Explanation:

F=ma where F is the force in newtons, m is the mass in kilograms (kg), and a is the acceleration

m=7.5kg

a=8.3m/s^2

Therefore, F=ma=7.5*8.3=62.25N

The amount of force is 62.25N or 62.25 newtons

what is the mass of an object with a density of 74 g/mL and a volume of 7 mL?

Answers

Answer:

518 g

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 74 × 7

We have the final answer as

518 g

Hope this helps you

A student walks 300 meters due east and then 100 meters due north,
then 500 meters due west. The total distance travelled by the student
-
is
meters.

Answers

Answer:

900 meter hhgffhffhhfcbjhggjdswexaazcgh

Answer:

900 meters

Explanation:

If you are talking about how many meters student walked then its 900 metes

But if you are talking about how many meters student travelled from the start point then its 200 meter

A projectile is fired horizontally off the top of a cliff with an initial velocity of 30 m/s. It hits the ground 2.0 seconds later. What is the height of the cliff?

Answers

Answer:no

Explanation:

On an alien planet, a simple pendulum of length 0.300 m has oscillation frequency 0.709 Hz. Find the period of the pendulum. Find the acceleration due to gravity on this planet's surface. What must be the length of a simple pendulum if its oscillation frequency is to be equal to that of an air-track glider of mass 0.450 kg attached to a spring of force constant 9.75 N/m?

Answers

Answer:

1.41s

5.95m/s

0.2746m

Explanation:

The time period

T = 1/f

= 1/0.709s

= 1.41 seconds

We have

T = 2π√l/g

T² = 4π²l/g

g = 4π²l/T²

g = 4x3.14²x0.300/1.41²

g = 5.95m/s² this is the acceleration due to gravity.

Then the time period of the glide

T2 = 2π√m/k

Length of pendulum = l

Time period T

T2 = 2π√l/g

Then T1 = T2

2π√m/k = 2π√l/g

M/k = l/g

L = g.m/k

L = 5.95x0.450/9.75

L = 0.2746

This must be the length of the simple pendulum

A segment of wire of total length 3.0 m carries a 15-A current and is formed into a semicircle. Determine the magnitude of the magnetic field at the center of the circle along which the wire is placed. a. 1.6 mu T b. 4.9 mu T c. 1.0 mu T d. 9.8 mu T e. 15 mu T

Answers

Answer:

c. 1.0 mu T

Explanation:

From, the ampere's  circuit law:

∫B.dl = μ₀ I

B.(2πr) = μ₀ I

where,

B = Magnetic Field = ?

r = radius of the circle = length of wire = 3 m

μ₀ = Permeability of free space = 4π x 10⁻⁷ Tm/A

I = Current = 15 A

Therefore,

B(2π)(3 m) = (4π x 10⁻⁷ Tm/A)(15 A)

B = 10 x 10⁻⁷ T

B = 1 x 10⁻⁶ T = 1 μT

Hence, the correct option is:

c. 1.0 mu T

Problem (8):
A projectile is fired at an angle of 53° above the horizontal with initial speed of 10.0 m/s. After
one second, what is X and Y components of the position of that projectile?
A60m 20 m
B. 6.0 m. 8.0 m
C. 3.0 m, 6.0 m
D.4.0 m, 3.0 m​

Answers

Answer:

x=6 m, y= 3 m

Explanation:

Projectile Motion

It's the type of motion that experiences an object launched near the Earth's surface and moves along a curved path under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and g the acceleration of gravity, then the components of the velocity at a given time t are:

[tex]v_x=v_o\cos\theta[/tex]

[tex]v_y=v_o\sin\theta-g.t[/tex]

And the components of the displacement are:

[tex]x=v_o\cos\theta .t[/tex]

[tex]\displaystyle y=v_o\sin\theta.t-\frac{g.t^2}{2}[/tex]

The projectile of the problem is fired at θ=53° with an initial speed of vo=10 m/s.

Thus, after 1 second, the components of the displacement are:

[tex]x=10\cos 53^\circ \cdot 1[/tex]

[tex]x\approx 6~m[/tex]

[tex]\displaystyle y=10\sin 53^\circ\cdot 1-\frac{9.8\cdot 1^2}{2}[/tex]

[tex]y\approx3~m[/tex]

Answer: x=6 m, y= 3 m

None of the options match this answer.

8.
'A 6.00 kg ball, A, moving at velocity 3.00 m/s due east collides with a 6.00 kg ball, B, at rest.
After the collision, A moves off at 40.0°N of E and ball B moves off at 50.0° S of E
please help me.​

Answers

Answer:

brrrrrakabrrrrrrrrra

Explanation:

Whoever answers correctly gets brainlist!

Answers

Infared = used by police

gamma = short wavelength

radio = largest wavelength

visible = only ones we can see

Answer: police use infred waves,

radio waves have largest wave length, the

only part of the spectrum seen by humans is visible waves

gamma waves have shortest wave length

Explanation:

What happens in a convection current?

Answers

Answer:

Convection currents are the result of differential heating. Lighter (less dense), warm material rises while heavier (more dense) cool material sinks. It is this movement that creates circulation patterns known as convection currents in the atmosphere, in water, and in the mantle of Earth.

Explanation:

What would the distance be if a bicyclist traveled 4.5 hours at a speed of 20.0km/h?

Answers

5.5 is the answer i think

Can power be negative in physics? I am doing a lab in which I run down the stairs as quickly as possible. They are 5.4m tall and my work is 5321.7 J. After calculating work, I got -5321.7 J. I am supposed to calculate my power used over 3 trials. The time for trial 1 was 4.69 and the seconds for trials 2 and 3 are 4.25. After calculating my power I got -1134.69 W and -1252.16 W. I am not sure if I got my power right. Is my power really negative or is my power positive?

Answers

Answer:

Yes.

Explanation:

A negative power would just represent a loss of power. So in your case it lost -1252.16 W

A computational model predicts the maximum potential energy a roller coaster car can have given its mass and its speed at the lowest point of its journey. Its mass is 350 kg, and it speed at a height of 0 m is 25 m/s. What is the prediction for its maximum potential energy?
109,375 J

765,625 J

218,750 J

87,750 J

Answers

Answer:

The prediction for its maximum potential energy is 109,375 J

Explanation:

Given;

mass of the coaster car, m = 350 kg

speed of the coaster car at the lowest point, v = 25 m/s

The coaster car will have maximum kinetic energy at the lowest point and based on law of conservation of mechanical energy, the maximum kinetic energy of the coaster car at the lowest point will be equal to maximum potential energy at the highest point.

[tex]K.E_{max} = P.E_{max}[/tex]

[tex]K.E_{max} = \frac{1}{2} mv^2\\\\K.E_{max} = \frac{1}{2} (350)(25)^2\\\\K.E_{max} =109,375 \ J[/tex]

[tex]Thus, P.E_{max} = 109,375 \ J[/tex]

Therefore, the prediction for its maximum potential energy is 109,375 J

An airplane takes off northwest from Dallas to Amarillo. This is an example of-

a. Speed
b. Velocity
c. Acceleration

Answers

Answer:

the answers is C. acceleration

A roller coaster has a vertical loop with radius 29.5 m.What is the minimum speed of the roller coaster car can have at the top of the loop if the passengers do not lose contact with the seats?
A) 10.0 m/s
B) 14.0 m/s
C) 17.0 m/s
D) 19.0 m/s

Answers

Answer:the  Minimum speed , v of the roller coster = 17.0 m/s --c

Explanation:

According to Newton's First law  of Motion which state that all object will remain at rest unless an external force is applied on the body to act otherwise.

Therefore the   Force exerted/ acting  on the surface of  the roller coaster will be equal to 0,

Net Force = 0

Remember that , Force = mg = Mv ²/r = 0

 Net Force =mv ² / r - mg = 0

mv²/ r - mg = 0

(diving through by m)

v²/r -g = 0

v² = gr

v= [tex]\sqrt{gr}[/tex]

where g, acceleration due to gravity= 9.8m/s2 and radius, r = 29.5m

v=  [tex]\sqrt{9.8m/s2 X 29.5m }[/tex]

v =[tex]\sqrt{ 289}[/tex]

v=  17.0 m/s

Therefore, the  Minimum speed , v of the roller coaster = 17.0 m/s

A ball rolls to the right across a grassy field slowing down as it does so. Which of the following must be true?

Answers

Answer: i could prolly answer if it made more sense. which of the following where?

Answer:

D: the ball is not accelerating because it is slowing down

Explanation:

if the was no friction, then the ball would most likely pick up speed and never stop, like it would with it being on a hill covered in ice, it would pick up speed and never slow down (well, it would slow down, just at a point where it looks like it would never stop.

A barrel of oil contains roughly 6.1x109 J. How many kW-hr is this? Answer in
units of kW-hr

Answers

Answer:

[tex]1.694*10^3KW/hr[/tex]

Explanation:

Formula:

[tex]KW/hr=E_{(change)}[/tex]

[tex]P=\frac{E}{t}[/tex]

[tex](KW)(s)=1000J[/tex]

[tex](3600)(KW)(s)=3600*1000J[/tex]

[tex]KW=3.6*10^6[/tex]

[tex]\frac{6.1*10^9}{3.6*10^6}=\frac{x}{1KW}[/tex]

[tex]1.694*10^3KW/hr[/tex]

Hope it helps

As you take the stoppered part of the tube up the staircase you begin to see the water level drop around the 4th floor. As you continue up it does not continue up with you but stays at a constant level. What does that mean?
a. The pressure in the tubing is equal to the barometric pressure.
b. The tubing was unable to supply any more water to the tube for use.
c. The pressure outside the tube is higher that the water pressure inside the tube.

Answers

Answer:

a. The pressure in the tubing is equal to the barometric pressure.

Explanation:

Since in the question it is mentioned that the if you take the stoppert part of the tube than the level of warer would be fall approx 4th floor and if it is continued than it wont be continue but remains constant.

Now here first we do that the tube i.e. connected to the bucket should be taken up. In the first instance, the bucket supplies the water to the tube but it would not increased far away to the level of the barometric pressure

Hence, the correct option is a.

The mass of an empty flask is 49.74 g. Filled with 120 cm 3 of acetone, the mass of the flask is found to be 144.78 g. What is the density of acetone?

Answers

Answer:

0.79g/cm³

Explanation:

Given parameters:

Volume of acetone = 120cm³

Mass of empty flask  = 49.74g

Mass of flask + acetone  = 144.78g

Unknown:

Density of acetone = ?

Solution:

Density is the mass per given volume of a substance. It is mathematically expressed as;

   Density  = [tex]\frac{mass}{volume}[/tex]  

     Mass of acetone  =( mass of flask + acetone)   - mass of empty flask

     Mass of acetone = 144.78  - 49.74  = 95.04g

Now insert the parameters and solve;

 Density  = [tex]\frac{95.04}{120}[/tex]   = 0.79g/cm³

Nicki rides her bike at a constant speed for 6 km. That part of her ride takes her 1 h. She then rides her bike at a constant speed for another 9
km. That part of her trip takes her 2 h. What is her average speed?

Answers

Answer:

24km/h

Explanation:

go it right on ingenuity 2020

On Earth, you can lift a 10 kg object. What is the mass of that object on the moon? Is mass independent from gravity?​

Answers

Explanation:

An object's weight depends on the pull of the gravitating object but the object's mass is independent of the gravity.

A train slows from 44 m/s to 19 m/s in 9 seconds. What is the train's acceleration? Show your work.

Answers

Answer:

a = 2.77 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f} =v_{o} -a*t[/tex]

where:

Vf = final velocity = 19 [m/s]

Vo = initial velocity = 44 [m/s]

a = acceleration [m/s²]

t = time = 9 [s]

Note: The negative sign in the above equation means that the train is decreasing its velocity.

19 = 44 - a*9

9*a = 44 -19

a = 2.77 [m/s²]

1. In a particular experiment to study the photoelectric effect, the frequency of the incident light and the temperature of the metal are held constant. Assuming that the light incident on the metal surface causes electrons to be ejected from the metal, what happens if the intensity of the incident light is increased?A. The work function of the metal decreases. B. The number of electrons emitted from the metal per second increases. C. The maximum speed of the emitted electrons increases. D. The stopping potential increases.2. In another experiment, the intensity of the incident light and the temperature of the metal are held constant. Assuming that the initial light incident on the metal surface causes electrons to be ejected from the metal, what happens if the frequency of the incident light is increased? A. The work function of the metal increases. B. The number of electrons emitted from the metal per second increases. C. The maximum speed of the emitted electrons increases. D. The stopping potential increases.

Answers

Answer: 1. B. The number of electrons emitted from the metal per second increases.

2. The maximum speed of the emitted electrons increases.

The stopping potential increases

Explanation:

Photoelectric effect is simply referred to as the emission of electrons that occurs when there's an electromagnetic radiation. An example of such electromagnetic radiation is when material is being hit by light.

Assuming that the light incident on the metal surface causes electrons to be ejected from the metal, the number of electrons emitted from the metal per second increases if the intensity of the incident light is increased.

Also, if the initial light incident on the metal surface causes electrons to be ejected from the metal, the maximum speed of the emitted electrons increases and the stopping potential increases.

In the flowchart representation of the scientific method (the one that embraces the use of constructing models), what does one do immediately after making observations?

Answers

Answer:

The correct answer is - ask a question based on observation and then postulate a hypothesis.

Explanation:

The scientific method is the step by step process to find an answer to any scientific question with the help of scientific investigation or experiment. The steps that make an investigation successful are should be in the correct order. These steps are as follows:

*Make an Observation

*Ask a Question

*Do Background Research

*Form a Hypothesis

*Conduct an Experiment

*Analyze Results and Draw a Conclusion

*Report Your Results

A sphere has a mass of 8.5 kg and a radius of 10cm. How much work is it necessary to do on the ball to get it to a speed of 6.0m/s?

Answers

Answer:

153J

Explanation:

Step one:

given data

mass m= 8.5kg

radius r= 10cm in meters = 0.01m

velocity v= 6m/s

The work done will be the same as the energy possessed by the sphere at such speed

Required

the work one in Joules

we know that

KE=1/2mv^2

KE=1/2*8.5*6^2

KE= 1/2*8.5*36

KE=306/2

KE=153J

In the picture below, sphere X swings down and collides with sphere Y. Identify the action and reaction forces. 

Action force: 
Reaction force: 

Answers

Answer:

Action force is force acting in one direction. Reaction force is force acting in the opposite direction.

A group of big city tenants were upset about rising rent for their apartments, and decided to play a prank on the Building Manager. They went up to the top floor of the
building, which was 176.4 m above the sidewalk, and waited. They wanted to drop the balloon at just the right time, so they needed to make a quick calculation. How many
seconds before the Building Manager walks to the spot should they drop the balloon?

Answers

Answer:

  t = 6 s

Explanation:

This is a free fall exercise

          y = y₀ + v₀ t - ½ g t²

If the balloon is released its initial velocity is zero, when it reaches the floor its height is also zero, we substitute

         0 = y₀ + 0  - ½ g t2

         t = √(2yo / g)

let's calculate

         t = √ (2 176.4 / 9.8)

         t = 6 s

the balloon must be released 6 s before the person reaches the building

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