1. A 500 N force applied to a box at a 50 degree angle above the horizontal surface. Find the x and y
components. Use the cheat sheet located in your blue resource folder, and show all work.

Answers

Answer 1

Answer:

The x and y components of the 500 N-force are 321.394 newtons and 383.023 newtons, respectively.

Explanation:

At first we present a figure describing the situation explained on statement, the x and y components of the force are determined by the following trigonometric expressions:

[tex]F_{x} = F\cdot \cos \alpha[/tex] (1)

[tex]F_{y} = F\cdot \sin \alpha[/tex] (2)

Where:

[tex]F[/tex] - Magnitude of the force, measured in newtons.

[tex]\alpha[/tex] - Direction of the force above the horizontal surface, measured in sexagesimal degrees.

If we know that [tex]F = 500\,N[/tex] and [tex]\theta = 50^{\circ}[/tex], then the components of the force is:

[tex]F_{x} = (500\,N)\cdot \cos 50^{\circ}[/tex]

[tex]F_{x} = 321.394\,N[/tex]

[tex]F_{y} = (500\,N)\cdot \sin 50^{\circ}[/tex]

[tex]F_{y} = 383.023\,N[/tex]

The x and y components of the 500 N-force are 321.394 newtons and 383.023 newtons, respectively.

1. A 500 N Force Applied To A Box At A 50 Degree Angle Above The Horizontal Surface. Find The X And Ycomponents.

Related Questions

What would the distance be if a bicyclist traveled 4.5 hours at a speed of 20.0km/h?

Answers

5.5 is the answer i think

A penny falls 380 meters. If dropped from rest, ignoring any air resistance, what is the velocity at which the penny hits the ground? Show your work.

Answers

Answer:

Vf = 86.34 [m/s]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f} ^{2} =v_{o} ^{2} +2*g*y[/tex]

where:

Vf = final velocity [m/s]

Vo = initial velocity = 0 (falls from the rest)

g = gravity acceleration = 9.81 [m/s²]

y = distance = 380 [m]

Vf² = 0 + (2*9.81*380)

Vf = 86.34 [m/s]

Note: The pisitive sign in the equation above means that the movement goes in the same direction of the gravity acceleration, therefore the velocity is increasing when the penny falls.

A train slows from 44 m/s to 19 m/s in 9 seconds. What is the train's acceleration? Show your work.

Answers

Answer:

a = 2.77 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f} =v_{o} -a*t[/tex]

where:

Vf = final velocity = 19 [m/s]

Vo = initial velocity = 44 [m/s]

a = acceleration [m/s²]

t = time = 9 [s]

Note: The negative sign in the above equation means that the train is decreasing its velocity.

19 = 44 - a*9

9*a = 44 -19

a = 2.77 [m/s²]

Cindy has been working for 8 years and she’s built up a huge emergency fund

Answers

Answer:The answer will be B :) hope this helps!

Explanation:

Accurate radiometric dating typically requires that a rock contains a measurable amount of __________.

Answers

Answer:

Both daughter and parent atoms

Explanation:

Daughter atoms are an offshoot of daughter elements, and are formed when a radioactive element undergoes radioactive decay. The new element is the daughter element, while the initial, the former element is the parent element.

Same analogy goes for daughter atoms and parent atoms..

Radiometric dating is also called radioactive dating or even radioisotope dating. It is a technique that is used to date materials like carbon or even rocks, that has trace radioactive impurities selectively incorporated into it when they were formed.

Radiometric dating is defined as the technique, which is used to date rocks, carbon, or radioactive impurities. The rocks that consist of parent and daughter atoms are used for accurate radiometric dating.

The correct statement for the blank is:

Accurate radiometric dating typically requires that rock contains a measurable amount of parent and daughter atoms.

It can be defined as:

1. Daughter atoms are formed when the radioactive element undergoes radioactive decay. The element formed is the daughter element from which it is formed is known as the parent element.

2. A radioactive isotope is also called radioactive dating, which is used to date rocks and radioactive elements. These elements are incorporated into the elements when they are formed.

Thus, the correct answer is parent and daughter atoms.

To know more about radioactive dating, refer to the following link:

https://brainly.com/question/3444297

Cylindrical rod has equal and opposite forces applied perpendicular to its circular ends. The forces are directed away from the rod, stretching the rod. What type of stress is this rod subject to:_________A) The rod is subject to shear stress. B) The rod is subject to tensile stress. C) The rod is subject to compressive stress. D) The rod is subject to bulk stress.

Answers

Answer:

B) The rod is subject to tensile stress

Explanation:

Tensile stress is the force induced in the body per unit area in response to externally applied force, which stretches the body.

Tensile stress is attached with tensile forces. It is makes material elongate along the axis of the applied load.

It is given as magnitude (F) of the force that is applied along an elastic rod divided by the cross sectional area (A) of the rod in a direction that is perpendicular to the applied force.

materials such as Doctile have the ability to withstand the load while brittle materials who not have the ability they fail before reaching the ultimate material strength.

Whoever answers correctly gets brainlist!

Answers

Infared = used by police

gamma = short wavelength

radio = largest wavelength

visible = only ones we can see

Answer: police use infred waves,

radio waves have largest wave length, the

only part of the spectrum seen by humans is visible waves

gamma waves have shortest wave length

Explanation:

A stone is dropped vertically downwards. What is the velocity of the rock after 4 seconds ? What is the displacement of the rock after 4 seconds ?

Answers

Answer:

Vf = 39.2 m/s

h = 78.4 m

Explanation:

Using first equation of motion for vertical motion:

Vf = Vi + gt

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 0 m/s

g = 9.8 m/s²

t = time taken = 4 s

Therefore,

Vf = 0 m/s + (9.8 m/s²)(4 s)

Vf = 39.2 m/s

Now, we use second equation of motion

h = Vi t + (1/2)gt²

where,

h = height covered = ?

Therefore,

h = (0 m/s)(4 s) + (1/2)(9.8 m/s²)(4 s)²

h = 78.4 m

what
material gives the soil its high fertility?

Answers

Answer:

Humus

Explanation:

Its Humus I believe. I remember learning something like this.

What is one question you would ask a professional athlete?

Answers

Answer:

Why do you do sports, when you could be a doctor and helping the sick children, or saving the worlds ocean?

Explanation:

How did you start your career as an athlete?

An airplane takes off northwest from Dallas to Amarillo. This is an example of-

a. Speed
b. Velocity
c. Acceleration

Answers

Answer:

the answers is C. acceleration

Calculate the radiation dosage (in grays) for a 63‑kg person who is exposed for 5.0 s to a 3.0 Ci source of beta radiation. Assume that 100% of the radiation is absorbed and that each beta particle has an energy of 1.5×10−13 J.

Answers

Answer:

1.32142x10^-3 Gy

Explanation:

Mass m = 63kg

Time t = 5.0s

Beta energy = 1.5x19^-13J

1 Ci = 3.7x10¹⁰

3.0Ci = 3x3.7x10¹⁰

= 11.1x10¹⁰decay/s

We have a total of 11.1x10¹⁰ beta particles produced per second

The question says there is 100% absorption

Et = (11.1x10¹⁰)x5x1.5x10^-13

= 0.08325

The radiation dose = Et/m

= 0.08325/63 kg

= 0.001321428J/kg

= 0.001321428 grays

Or 1.32142x10^-3 Gy

The radiation dose of the person is 1.31 x 10⁻⁴ J/kg.

Radiation dose

The radiation does is the ratio of the total dose to the mass of the person exposed to the radiation.

3 Ci beta radiation = 3 x (3.7x10¹⁰) = 11.1 x 10¹⁰decay/s

Total beta energy absorbed in 5 s

Et = (11.1x10¹⁰) x 5 x 1.5 x 10⁻¹³

Et = 8.25 x 10⁻³ J

Radiation dose of the person is calculated as follows;

Rd = Et/m

Rd = (8.25 x 10⁻³ J) / 63

Rd = 1.31 x 10⁻⁴ J/kg

Learn more about radiation dose here: https://brainly.com/question/1421857

1. In a particular experiment to study the photoelectric effect, the frequency of the incident light and the temperature of the metal are held constant. Assuming that the light incident on the metal surface causes electrons to be ejected from the metal, what happens if the intensity of the incident light is increased?A. The work function of the metal decreases. B. The number of electrons emitted from the metal per second increases. C. The maximum speed of the emitted electrons increases. D. The stopping potential increases.2. In another experiment, the intensity of the incident light and the temperature of the metal are held constant. Assuming that the initial light incident on the metal surface causes electrons to be ejected from the metal, what happens if the frequency of the incident light is increased? A. The work function of the metal increases. B. The number of electrons emitted from the metal per second increases. C. The maximum speed of the emitted electrons increases. D. The stopping potential increases.

Answers

Answer: 1. B. The number of electrons emitted from the metal per second increases.

2. The maximum speed of the emitted electrons increases.

The stopping potential increases

Explanation:

Photoelectric effect is simply referred to as the emission of electrons that occurs when there's an electromagnetic radiation. An example of such electromagnetic radiation is when material is being hit by light.

Assuming that the light incident on the metal surface causes electrons to be ejected from the metal, the number of electrons emitted from the metal per second increases if the intensity of the incident light is increased.

Also, if the initial light incident on the metal surface causes electrons to be ejected from the metal, the maximum speed of the emitted electrons increases and the stopping potential increases.

The Doppler effect is the change in sound _____ caused by the motion of the sound source, motion of the listener, or both.
pitch
frequency
amplitude
speed

Answers

Frequency.
..........

A barrel of oil contains roughly 6.1x109 J. How many kW-hr is this? Answer in
units of kW-hr

Answers

Answer:

[tex]1.694*10^3KW/hr[/tex]

Explanation:

Formula:

[tex]KW/hr=E_{(change)}[/tex]

[tex]P=\frac{E}{t}[/tex]

[tex](KW)(s)=1000J[/tex]

[tex](3600)(KW)(s)=3600*1000J[/tex]

[tex]KW=3.6*10^6[/tex]

[tex]\frac{6.1*10^9}{3.6*10^6}=\frac{x}{1KW}[/tex]

[tex]1.694*10^3KW/hr[/tex]

Hope it helps

A projectile is fired horizontally off the top of a cliff with an initial velocity of 30 m/s. It hits the ground 2.0 seconds later. What is the height of the cliff?

Answers

Answer:no

Explanation:

A 0.900-V potential difference is maintained across a 1.5m length of 2
tungsten wire that has a cross-sectional area of 0.600 mm . What is the current in the wire?

Answers

Answer:

I = 6.42 A

Explanation:

Given that,

Potential difference, V = 0.9 V

Length of the wire, l = 1.5 m

Area of cross section, [tex]A=0.6\ mm^2=6\times 10^{-7}\ m^2[/tex]

We need to find the current in the wire. Let I is current. We can find it using Ohm's law as follows :

V = IR

Where R is the resistance of the wire

[tex]I=\dfrac{V}{R}\\\\I=\dfrac{V}{\rho \dfrac{l}{A}}\\\\I=\dfrac{0.9}{5.6\times 10^{-8}\times \dfrac{1.5}{6\times 10^{-7}}}\\\\I=6.42\ A[/tex]

So, the current in the wire is 6.42 A.

Someone please help asap
Question 4: If a body of mass 4 kg moves at a velocity of 25 mls and has a 2 points
completely inelastic collision with a body of mass 10 kg, the final velocities
of both the bodies is 14 m/s. Calculate the initial velocity of the body of
mass 10 kg."

Answers

Huhhhh this is confusing ummm hello I guess

A torque of 0.97 N m is applied to a bicycle wheel of radius 35 cm and mass 0.75 kg. Assuming the wheel can be modelled as a hoop, find the angular acceleration of the wheel.

Answers

Answer:

11 rad/s^2 approx.

Explanation:

Given

torque,τ= 0.97N

radius r= 35cm to m= 0.35m

mass m= 0.75kg

Required

angular acceleration

First, we need the  moment of inertial of the wheel

I=mr^2

I=0.75*0.35^2

I=0.75*0.1225

I=0.09kgm^2

Secondly, the angular moment of inertial is expressed as

a=τ/I

a=0.97/0.09

a=10.77rads/s^2

a=11 rad/s^2 approx.

Can power be negative in physics? I am doing a lab in which I run down the stairs as quickly as possible. They are 5.4m tall and my work is 5321.7 J. After calculating work, I got -5321.7 J. I am supposed to calculate my power used over 3 trials. The time for trial 1 was 4.69 and the seconds for trials 2 and 3 are 4.25. After calculating my power I got -1134.69 W and -1252.16 W. I am not sure if I got my power right. Is my power really negative or is my power positive?

Answers

Answer:

Yes.

Explanation:

A negative power would just represent a loss of power. So in your case it lost -1252.16 W

A sound wave travels in a straight line at a constant speed of 660 mph. What is
the acceleration of the sound wave? Explain your answer.

Answers

Answer:

a = 0

Explanation:

The velocity of a sound wave in a straight line is 660 mph. The wave is moving with a constant velocity. It means that the change in velocity is equal to 0.

We know that acceleration of an object is equal to the change in velocity divided by time taken. But here the change in velocity is 0. As a result the acceleration of the sound wave is 0.

On Earth, you can lift a 10 kg object. What is the mass of that object on the moon? Is mass independent from gravity?​

Answers

Explanation:

An object's weight depends on the pull of the gravitating object but the object's mass is independent of the gravity.

A sled with a mass of 25.0 kg rests on a horizontal sheet of essentially frictionless ice. It is attached by a 5.00-m rope to a post set in the ice. once given a push, the sled revolves uniformly in a circle around the post. If the sled makes five complete revolutions every minute, find the F exerted on it by the rope.​

Answers

Answer:

The value is  [tex]F = 34.3 \ N[/tex]

Explanation:

From the question we are told that

    The mass of the shed is  [tex]m = 25 \ kg[/tex]

    The length of the rope is  [tex]l = 5.0 \ m[/tex]

    The angular speed of the shed is [tex]w = 5 rev/minute = \frac{2* \pi * 5}{60 }= 0.524 \ rad/sec[/tex]

Generally the force exerted on the shed is mathematically represented as

     [tex]F = m * w^2 * l[/tex]

=>  [tex]F = 25 * 0.524^2 * 5[/tex]

=>  [tex]F = 34.3 \ N[/tex]    

The magnitude of the centripetal force on the sled by the rope is 34.3 N.

The given parameters:

mass of the sled, m = 25 kglength of the rope, r = 5 mnumber of revolution per minute, N = 5

The angular speed of the sled is calculated as follows;

[tex]\omega = 5 \ \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1 \min}{60 \ s} \\\\\omega = 0.524 \ rad/s[/tex]

The magnitude of the centripetal force on the sled by the rope is calculated as follows;

[tex]F = ma_c\\\\F = m\omega ^2 r\\\\F = 25 \times (0.524)^2 \times 5\\\\F = 34.3 \ N[/tex]

Learn more here:https://brainly.com/question/20905151

30.6*X+-2.56
Pls help

Answers

Answer:  10.16

Explanation:

What is an atom's nucleus made of?
(2 points)
protons and electrons
protons only
protons and neutrons
neutrons only

Answers

Answer:

nucleus made of protons and neutrons because the chemical atom is determined my a number

A ball rolls to the right across a grassy field slowing down as it does so. Which of the following must be true?

Answers

Answer: i could prolly answer if it made more sense. which of the following where?

Answer:

D: the ball is not accelerating because it is slowing down

Explanation:

if the was no friction, then the ball would most likely pick up speed and never stop, like it would with it being on a hill covered in ice, it would pick up speed and never slow down (well, it would slow down, just at a point where it looks like it would never stop.

True or false? An electric current is a continuous flow of electric charges through a material.

Answers

Answer is... if True
The Answer is True.

Which phrase best completes the diagram?
Drawbacks of Trade Barriers
Less consumer choice
Retaliatory trade barriers
A. Domestic jobs put at risk
B. More competition for domestic industries
O
C. Increased reliance on other countries
D. Reduced economic efficiency

Answers

Answer:D

Explanation:

just got it right

Answer:D

Explanation:

taking the test

A roller coaster has a vertical loop with radius 29.5 m.What is the minimum speed of the roller coaster car can have at the top of the loop if the passengers do not lose contact with the seats?
A) 10.0 m/s
B) 14.0 m/s
C) 17.0 m/s
D) 19.0 m/s

Answers

Answer:the  Minimum speed , v of the roller coster = 17.0 m/s --c

Explanation:

According to Newton's First law  of Motion which state that all object will remain at rest unless an external force is applied on the body to act otherwise.

Therefore the   Force exerted/ acting  on the surface of  the roller coaster will be equal to 0,

Net Force = 0

Remember that , Force = mg = Mv ²/r = 0

 Net Force =mv ² / r - mg = 0

mv²/ r - mg = 0

(diving through by m)

v²/r -g = 0

v² = gr

v= [tex]\sqrt{gr}[/tex]

where g, acceleration due to gravity= 9.8m/s2 and radius, r = 29.5m

v=  [tex]\sqrt{9.8m/s2 X 29.5m }[/tex]

v =[tex]\sqrt{ 289}[/tex]

v=  17.0 m/s

Therefore, the  Minimum speed , v of the roller coaster = 17.0 m/s

The mass of an empty flask is 49.74 g. Filled with 120 cm 3 of acetone, the mass of the flask is found to be 144.78 g. What is the density of acetone?

Answers

Answer:

0.79g/cm³

Explanation:

Given parameters:

Volume of acetone = 120cm³

Mass of empty flask  = 49.74g

Mass of flask + acetone  = 144.78g

Unknown:

Density of acetone = ?

Solution:

Density is the mass per given volume of a substance. It is mathematically expressed as;

   Density  = [tex]\frac{mass}{volume}[/tex]  

     Mass of acetone  =( mass of flask + acetone)   - mass of empty flask

     Mass of acetone = 144.78  - 49.74  = 95.04g

Now insert the parameters and solve;

 Density  = [tex]\frac{95.04}{120}[/tex]   = 0.79g/cm³

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